In a process for the manufacture of chlorine by direct oxidation of HCl with air over a catalyst to form C12 and H2O (only), the exit product is composed of HCI (4.4%), CZ (19.8%), 02 (4,0%), and N2 (52.0%). What was?
The process for the manufacture of chlorine by direct oxidation of HCl with air over a catalyst to form C12 and H2O (only) is known as catalytic oxychlorination. The exit product from this reaction is composed of HCl (4.4%), CZ (19.8%), 02 (4,0%), and N2 (52.0%). In order to determine what was the reactant feed composition, we must first look at how these components interact in the reaction .
HCl reacts with O2 in the presence of a catalyst to form C12 and water according to the following equation: 2HCl + 02 ->C12+ 2H20. This means that if we know the amount of HCl present in our exit product then we can calculate how much oxygen was reacted since the molar ratio between them is 1:1; therefore 4.4% of HCI would require 4% O2 for complete reaction (Lin et al., 2017). Additionally, since Nitrogen makes up 52% of our exit product then it follows that it must have been present as an inert gas in equal parts to oxygen i.e 52%.
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